A(x)=2x^2+50x

Solution for A(x)=2x^2+50x equation:

(A)=2A^2+50A

We move all terms to the left:

(A)-(2A^2+50A)=0

We get rid of parentheses

-2A^2+A-50A=0

We add all the numbers together, and all the variables

-2A^2-49A=0

a = -2; b = -49; c = 0;
Δ = b2-4ac
Δ = -492-4·(-2)·0
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2401}=49$
$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-49)-49}{2*-2}=\frac{0}{-4}
=0
$
$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-49)+49}{2*-2}=\frac{98}{-4}
=-24+1/2
$